By rearranging the formula for Schwarzschild radius, I was able to determine the mass of the black hole produced by Nightmare. The formula is r = 2GM/c^2, but rearranging it to M = cr^2/G is what I need to work with. M is mass, c is the speed of light, which I must use because I was testing this out by working with 10 kilograms using r = 2GM/c^2. The only way I could return to 10 kilograms was by using c. Next, r is radius and G is the gravitational constant. I still need the radius, which I was able to capture an image of. I compared it with Samus’ height, whose pixels were 112. The black hole was 362 pixels, or 6.14 meters in diameter. This makes its radius 3.07 meters.

M = (299,792,458 m/s^2)(3.07 m^2) / (6.67 × 10^-11 N m^2/kg^2)
M = 1.379 × 10^19 kg.

With this information, I can now find out the surface gravity of the black hole.

g = (6.67 × 10^-11 N m^2/kg^2)(1.379 × 10^19 kg.)/(3.07 m.)^2
g = 9.761 × 10^7 m/s^2

One of the things worth noting is in the first battle against Nightmare, Samus has not yet activated the gravity feature. At this time, Nightmare will create a localized gravity field. In the second battle, Nightmare does the same thing, but he’s also capable of creating a black hole. When he does this, he is unable to create a localized gravity field, probably because the gravity has been condensed into a smaller location, which I refer to as a black hole. If this is the case, then Samus can probably withstand this surface gravity, or it’s likely that because the diameter is greater, the gravity is greatly lessened.

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